4n^2-5n-1=0

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Solution for 4n^2-5n-1=0 equation: 



4n^2-5n-1=0

a = 4; b = -5; c = -1;
Δ = b2-4ac
Δ = -52-4·4·(-1)
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{41}}{2*4}=\frac{5-\sqrt{41}}{8}
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{41}}{2*4}=\frac{5+\sqrt{41}}{8}
$

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